### Video instructions and help with filling out and completing Why Form 2220 Consecutive

Instructions and Help about Why Form 2220 Consecutive

How you doing thank you for tuning in to this here video presentation by mr. Larry Whittington or as he want to be known mr. wit mr. Whittington's know all about mathematics and that is why he founded their Fort Bend to Turing's today we're going to learn about word problems not to kind where you curse people out but the mathematical cans they can I don't be understanding at all all right get your ink pen in your pencil ready take notes because you thing to learn for mr. wits hello ladies and gentlemen this is Larry Whittington with Fort Bend tutoring and today's lesson is going to be about consecutive integer word problems this is going to be part two of our word problem series anytime we're dealing with consecutive integers please understand that we're just talking about numbers that follow one another for instance 6 7 & 8 are consecutive integers so here in our first problem it says the sum of three consecutive integers is 84 find the integers the first thing I'm going to do is define my three consecutive integers so I will have my first integer as my unknown that's going to be my variable X the second integer that I'll have is going to be one more than my first integer so I can define that as X plus 1 all right then for my third consecutive integer that's going to be two more than my original value so I'm going to define that as X plus 2 so this will ensure that my first value and my second value and my third value will definitely be consecutive integers all right we were told that the sum of these three consecutive integers is 84 which means we need to add these three values together and have it equal to 84 so here's going to be our equation we'll have X plus X plus 1 which is the second value plus X plus 2 all equal to 84 from there I'm going to combine my like terms and then solve for the variable so I have one two three X's so adding those together you'll have 3x then combining one plus two that'll be a positive 3 and that equals to 84 from there I'll be solving this two-step equation here by subtracting three to both sides of the equal sign my threes will cancel out on the left side and then I'll be bringing down my 3x the term with a variable in it which now equals 284 minus 3 which is 81 my next step is then to divide both sides by 3 so once I divide by 3 I end up with X equaling 227 so I now know that my smallest value of these 3 consecutive integers is 27 so let's go ahead and set that up go back to where we have our values defined so the first value is X which we now know is 27 then if I were to add 1 to 27 I would end up with 28 if I were to add 2 to 27 I would end up with 29 so the 3 consecutive integers that add to 84 is 27 28 and 29 so those are our answers to the question 27 28 and 29 that's it that was problem number one ladies and gentlemen done and done let's check out proud number 2 in front of the 2 it says if the larger of two consecutive integers is subtracted from twice the smaller the result is 21 find the integers so here I'm only dealing with two consecutive integers so the first thing I want to do once again is define my values so I have my first value which is going to be X whereas my second consecutive integer will be X plus 1 remember consecutive integers are separated by 1 so I start out with X and then my next one is X plus 1 from there we're going to go ahead and set up our equation it says if the larger of the two consecutive integers which in this case would be X plus 1 is subtracted from twice the smaller the result is 21 anytime you have the phrase subtracted from you always put the second part first so keep in mind phrases such as less than and subtracted from the second part of that sentence it will definitely go first so in this sentence the second part is twice the smaller so that's the part I'm going to put first so I'll write this as 2x twice the smaller minus the larger of the two consecutive integers which is X plus one you'll need parentheses around that of greater value that X plus one so that we can find the opposite of it that's what that minus sign is that negative sign is taking the opposite of our larger consecutive integer so we now have two X minus the quantity of X plus one and remember it's supposed to equal to 21 so once I have this equation here we'll go ahead and solve it by first of all doing my favorite property in the world the distributive property so I'm going to get my arrows popping ladies and gentlemen so I'll rewrite this now as 2x minus X minus 1 equals 221 remember that negative in front of the parenthesis is negative 1 and that is being multiplied times everything inside of the parenthesis there my next step is to combine my like terms so I know that 2x minus X combining these two terms here will give me X so now we have X minus 1 equals 221 and from there we're going to add 1 to both sides of the equal sign so adding 1 to both sides of the equals sign gives me a result that is x equals to 22 so once I have my value of 22 we